I have string
ss='/users/parun/kk/jdk/bin/\x1b[01;31m\x1b[kjava\x1b[m\x1b[k'
How to get output
'/users/parun/kk/jdk/bin' only from the above
I tried
import re
re.split(r'\/\\')
But not working
CodePudding user response:
A regex search might be the best option here:
ss = '/users/parun/kk/jdk/bin/\x1b[01;31m\x1b[kjava\x1b[m\x1b[k'
path = re.findall(r'^.*/jdk/bin', ss)[0]
print(path) # /users/parun/kk/jdk/bin