find the largest consecutive occurrence of the same number in list without import any modules. I have this code

def reads():
lst=[] #create empty list

flag=True #create flag
N1=input("Input a number to add to list or 0 to stop: ") #read value
while flag: #check if invalid or not
    
    if not N1.isdigit():
        print("Invalid input")
        N1=input("Input a number to add to list or 0 to stop: ") #re read if invalid
    elif N1=="0": #stop if 0
        flag=False
    else:
        lst.append(N1) #add to empty list if valid
        N1=input("Input a number to add to list or 0 to stop: ") # re read
lst=list(map(int, lst)) #convert to integer
return lst #return

def long(lst):
newx=0 #count
x=lst[0] 
max1=0 #to save the how many number dupilicted
num=lst[0] #to save which number is
for i in range(1,len(lst)):
    if x==lst[i]: 
        
        newx=newx 1
    else:
        newx=newx 1
        if max1<newx:
            max1=newx
            num=x
            x=lst[i]
            newx=0
        else:
            newx=0
            x=lst[i]
return max1,num

def main(): # to call other functions and display the results
x=reads() 
m,a=long(x)
print("List: ",x)
print("The number is: ",a)
print("The largest size of consecutive numbers: ", m)
main()

the program run perfectly but there is mistake if I input 1 1 2 3 4 4 4 0 the list will be,

lst=[1,1,2,3,4,4,4]

and output must be

The number is: 4
The largest size of consecutive numbers: 3

but it be like that:

The number is: 1
The largest size of consecutive numbers: 2

the problem in long() function

CodePudding user response：

Try with this approach:

def long(lst):
    max_count = 1
    max_num = lst[0]
    count = 1
    for prec, num in zip(lst[:-1], lst[1:]):
        if num != prec:
            if count > max_count:
                max_count = count:
                max_num = prec
            count = 1
        else:
            count  = 1
    return max_num, max_count

CodePudding user response：

cont_cnt will continuosly count numbers in the input list, resetting the counter if a number differ from the the previous one. max_num then selects the max. The default=(None, None) is returned if the list is empty.

def cont_cnt(lst):
    prev = object() # guaranteed not to be present in the list
    for x in lst:
        if x != prev:
            count = 0 
            prev = x 
        count  = 1
        yield (count, x)

def max_num(lst):
    count, number = max(cont_cnt(lst), default=(None, None))
    print(f"Max: {number=}, {count=}")

max_num([1,1,2,3,4,4,4])
max_num([])