how to try...catch a feign exception and return only the status code and the erro message-CodePudding

I'm working on a SpringBootApplication. In this app I have 4 micro-services using Feign to communicate between eachothers. In a Controller I have a piece of code like this below, to catch exceptions and return it to the view, in case something is wrong.

        try {
            patientDTO = patientProxyFeign.getPatientById(id);
            noteDTOList = historyProxyFeign.getAll(id);
            assessmentDTO = assessmentProxyFeign.getPatientAssessment(id);
        } catch (Exception e) {
            log.error(""   e.getMessage());
            model.addAttribute("errorMsg", e.toString());
            return "error/error";
        }

If there is an exception I got a message like this to the view :

feign.FeignException$NotFound: [404] during [GET] to [http://localhost:8081/patient/12000] [PatientProxyFeign#getPatientById(Integer)]: [{"timestamp":"2021-12-16T16:21:27.790 00:00","status":404,"error":"Not Found","path":"/patient/12000"}]

What I want to do, is to get only the status code and the message "not found".

Is someone got an idea how to do it ? (Search on google, but seems to be too specific. I probably don't use the right keywords.)

CodePudding user response：

You can get the status by calling e.status() and then you can switch-case the status and get a message based on that. You could also build a Map of <Integer, String> and get the message by status. To read about FeignException more kindly visit https://github.com/OpenFeign/feign/blob/master/core/src/main/java/feign/FeignException.java

And it is strongly advisable to be specific about what you catch:

} catch (FeignException e) {