But my query only get 1 row for each table like this:
As you can see, there are 2 tables for 1003 because it has 2 rows. It should be only one (1) table of 1003 with 2 rows. How do I fix this? EXPECTED RESULT:
// Attempt select query execution
$query = "SELECT model, brand_code FROM smartphone GROUP BY model";
if($result = mysqli_query($db, $query))
{
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
?>
<?php echo $row["brand_code"]?>
<table id="table_stock" >
<thead>
<tr>
<th>Model</th>
</tr>
</thead>
<tbody>
<tr>
<td><?php echo $row["model"]?></td>
</tr>
</tbody>
</table><br>
<?php
}
/// Free result
mysqli_free_result($result);
}
else
{
echo "<td class='no_record' colspan='7'>No records found.</td>";
}
}
else
{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
CodePudding user response:
you need additional loop. Also in the first query you need to use group by codes.
$query = "SELECT model, brand_code FROM smartphone GROUP BY brand_code";
if($result = mysqli_query($db, $query))
{
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
?>
<?php echo $row["brand_code"]?>
<table id="table_stock" >
<thead>
<tr>
<th>Model</th>
</tr>
</thead>
<tbody>
<?php
if ($result1 = mysqli_query($db, "SELECT DISTINCT model, brand_code FROM smartphone WHERE brand_code={$row["brand_code"]}"))
{
while ($row1 = mysqli_fetch_array($result1))
{
?>
<tr>
<td><?php echo $row1["model"]?></td>
</tr>
<?php
}
mysqli_free_result($result1);
}
?>
</tbody>
</table><br>
<?php
}
/// Free result
mysqli_free_result($result);
}
else
{
echo "<td class='no_record' colspan='7'>No records found.</td>";
}
}
else
{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
CodePudding user response:
You have at least 5 problems here,
[edit: problem 1 removed & changed sample based on extended answer]
Inside your while { ... }
loop, you're printing an entire table, when you should only be printing the <tr>...</tr>
part there. This is what causes additional table(s).
And 3rd problem: your "no_record" line is a loose <td>
. Not only isn't it inside the table (which is covered in problem #2), it's also not wrapped with a <tr>
.
4th problem: You're randomly printing the echo $row["brand_code"]
outside of the table.
5th problem: you're printing raw data from the database as if it is valid html, it more than likely is not. it has to be probably encoded with htmlentities
/htmlspecialchars
.
Quick & dirty fixed version:
function tableOpen($row) {
printf( '<h1>%s</h1>', htmlentities($row["brand_code"]) );
echo '<table id="table_stock" >';
echo '<thead>';
echo '<tr>';
echo '<th>Model</th>';
echo '</tr>';
echo '</thead>';
echo '<tbody>';
}
function tableClose() {
echo '</tbody>';
echo '</table><br>';
}
// Attempt select query execution
$query = "SELECT model, brand_code FROM smartphone ORDER BY brand_code";
$lastBrand = null;
if ($result = mysqli_query($db, $query)) {
if (mysqli_num_rows($result) > 0) {
if ($lastBrand !== $row["brand_code"] && !is_null($lastBrand)) tableClose();
if ($lastBrand !== $row["brand_code"]) tableOpen($row);
$lastBrand = $row["brand_code"];
while ($row = mysqli_fetch_array($result)) {
echo '<tr>';
printf( '<td>%s</td>', htmlentities($row["model"]) );
echo '</tr>';
}
tableClose();
/// Free result
mysqli_free_result($result);
} else {
echo '<p >No records found.</p>';
}
} else {
echo "ERROR: Not able to execute \$query: <br>" . htmlentities($query) . '<br>' . htmlentities(mysqli_error($link));
}