What's a simple way to create 100 .txt files with 1 random number in each of them-CodePudding

I asked a similar question before, but the answers that I got weren't exactly what I was looking for. I want to create 100 .txt files with 1 random number in each of those files and assign them permissions based on the number inside the file. I used:

#!/bin/bash
rm -r -f .txt
touch {1..100}.txt
r=$RANDOM

to create new files each time the script is ran and assigned random number to "r". How do I paste a different number into each file. I'm not sure if I need to use echo or shuf to do it.

After that I need to check if the random number is divisible by 2 and 3 and give the files permissions based on that. I intend to use:

chmod 000 {1..100}.txt
if ((r % 2 == 0))
then echo chmod  rw {1..100}.txt
elif ((r % 3 ==0))
then chmod 777 {1..100}.txt
else chmod  w {1..100}

but I'm not sure if that works either.

CodePudding user response：

What's a simple way to create 100 .txt

Iterate over files and output the numbers.

for ((i = 1; i <= 100;   i)); do
  echo "$RANDOM" > "$i.txt"
done

CodePudding user response：

Using chmod can be done with code similar to the code in your question (changing it for 1 file each time and adding a fi). I skipped the chmod 000 and assign the correct mode at once.

for ((i = 1; i <= 100;   i)); do
  r="$RANDOM"
  echo "$r" > "$i.txt"
  if ((r % 2 == 0)); then
    chmod 666 "$i.txt"
  elif ((r % 3 ==0)); then
    chmod 777 "$i.txt"
  else
    chmod 222 "$i.txt"
  fi
done