I have a query that returns one JSON column named record
, which is generated by a subquery.
SELECT record FROM (my json query) records;
Each record contains an array of tag objects:
{
"tags": [
{
"id": 3,
"name": 'foo'
},
{
"id": 10,
"name": 'bar'
}
],
// other props
}
I want to modify my query to select all records
where tags
contains a tag with a specific ID but I'm not sure how to go about that without adding another subquery. Are there any functions or operations I'm missing that can make this possible using just the where clause?
In pseudo-code, is there anything like this I can do?
SELECT record FROM (my json query) records
WHERE 3 = ANY(get_ids_from_objects(record->'tags', 'id'));
For code reasons, I'd also prefer not to have to modify the subquery that creates the JSON structure, which is why I've excluded it.
CodePudding user response:
You can use the contains operator @>
select *
from (your query)
where record @> '{"tags": [{"id": 3}]}'
This assumes that the column record
is of type jsonb
(which it should be). If it's not, you need to cast it: record::jsonb