how to print loading with dots appearing and disappearing-CodePudding

I want to create a python script that print loading with dots appearing 1 by 1 and disappering them 1 by 1. I know how to disappear all of them but I want them them to go back 1 by 1.

Here is the code:-


for x in range(5):
    for y in range(4):
        dot = "."*y
        loading = (f"Loading {dot}")
        print(loading   "   ", end = '\r')
        time.sleep(1)

CodePudding user response：

You could define a function that returns a "zigzag" sequence that corresponds to the number of dots you want. The divmod builtin comes in handy here. (If you remove the if statement from the zigzag function, you get the same behavior you had before.)

This function also avoids the need for nested loops, which also makes it easy to print out an infinite loading sequence (since you can just increment a counter).

I'm also using .ljust(12) (where 12 is the length of "Loading " plus 4, the maximum number of dots) to left-justify the string that's printed on every line to the correct length instead of just "blindly" adding a number of spaces.

import time


def zigzag(counter, maximum):
    iteration, step = divmod(counter, maximum)
    if iteration % 2 == 1:  # go backwards every other iteration
        return maximum - step
    return step


for x in range(20):
    n_dots = zigzag(x, 4)  # up to 4 dots
    message = f"Loading {'.' * n_dots}"
    print(message.ljust(12), end='\r')
    time.sleep(.1)

This prints out

Loading
Loading .
Loading ..
Loading ...
Loading ....
Loading ...
Loading ..
Loading .
Loading

etc.

CodePudding user response：

I implemented the part that outputs dots in your code by making it a function.

import time

def dotmove(n):
    dot = "."*n
    loading = (f"Loading {dot}")
    print(loading   "   ", end = '\r')
    time.sleep(1)

for x in range(5):
    for y in range(4):
        dotmove(y)
    for z in range(2,  0, -1):
        dotmove(z)

CodePudding user response：

A more simplified version

import time
def load(dot_lenth=type(int),delay=1):
  dot=""
  for i in range(dot_lenth):
    print(f"Loading{dot}",end="\r")
    dot ="."
    time.sleep(delay)
    
  for i in reversed(range(dot_lenth)):
    print(f"Loading{dot[0:i]} ",end="\r")
    time.sleep(delay)
load(20,0.1)