I have a userform with RGB values to be assigned to shapes that will be later created by the macro:
Private Sub UserForm_Initialize()
With lstChosenColor
lstChosenColor.AddItem "RGB(0, 0, 0)"
lstChosenColor.AddItem "100, 100, 100" 'different from the above to show one alternative of my trials
End With
End Sub
However I do not know how to insert the selected value into the macro itself. I tried in many ways:
Dim lstChosenColor As String 'somewhere else i saw it as Long, tried but without success
' Dim ChosenColor As String
' ChosenColor = lstChosenColor 'I tried this one, too
If lstChosenColor = False Then
MsgBox "No Color Selected"
Else: New_Shape.Fill.ForeColor.RGB = lstChosenColor.Selected 'I tried also 'New_Shape.Fill.ForeColor.RGB = lstChosenColor and 'New_Shape.Fill.ForeColor.RGB = RGB(lstChosenColor)
End If
Set New_Shape = myDocument.Shapes.AddShape(Type:=msoShapeOval, Left:=Shp_Cntr - ((Shp.Width 2) / 2), Top:=Shp_Mid - ((Shp.Width 2) / 2), Width:=Shp.Width, Height:=Shp.Width)
' New_Shape.Fill.ForeColor.RGB = RGB(lstChosenColor) 'I commented this as it is part of a repeating block for a various number of shapes and I thought I could assign the RGB value above
Could anyone please advise?
CodePudding user response:
If you use (eg) "100, 100, 100" as the value you can do something like:
Dim v, arr
v = lstChosenColor.Value 'get selected value
arr = Split(Replace(v, " ", ""), ",") 'remove any spaces and split to array
'assign each array element as an argument to RGB()
New_Shape.Fill.ForeColor.RGB = RGB(CLng(arr(0)), CLng(arr(1)), CLng(arr(2)))