Is there a way to make a matrix without a repeating value?-CodePudding

import random

def main():
values = [
            [0, 0, 0, 0, 0],
            [0, 0, 0, 0, 0],
            [0, 0, 0, 0, 0],
            [0, 0, 0, 0, 0],
            [0, 0, 0, 0, 0]
        ]
for r in range(5):
    for c in range(5):
        rand = random.randint(1, 25)
        if values[r][c] != rand:
            values[r][c] = rand

        

for i in range(5):
    print("\n")
    for j in range(5):
        print("\t"   str(values[i][j]), end=" ")

main()

This code should've printed a 5 x 5 matrix with a range of 1-25 without repeating the number. For some reason, the if command I did put in did not randomize it. Can someone help me with the solution?

CodePudding user response：

Try this:

from random import shuffle

numbers = list(range(1, 26))
shuffle(numbers)
values = [[numbers[i * 5   j] for j in range(5)] for i in range(5)]

First you create a list of numbers from 1 to 25. Then you randomly shuffle it. And finally you create a matrix out of it.

CodePudding user response：

I interpret the question as not having any number appear more than once in the matrix? The following is to clarify my understanding.

import random


def main():
    values = [
        [0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0]
    ]

    for r in range(5):
        for c in range(5):
            rand = random.randint(1, 25)
            # Modify with while loop to ensure number appears only once.
            if values[r][c] != rand:
                values[r][c] = rand

    for i in range(5):
        print("\n")
        for j in range(5):
            print("\t"   str(values[i][j]), end=" ")

main()

Output not desired because for example 4 and 13 appear more than once?

    20  5   12  11  14 

    14  20  25  4   4 

    11  18  22  13  8 

    22  18  12  13  13 

    20  1   19  23  17