Pass list elements as arguments of a function one by one-CodePudding

Suppose I have a function to calculate the square of a certain number. Now, I have a list of, for example, 100 numbers that I need to pass as the arguments. How do I pass each element of the list, one by one, as the argument to get the results?

CodePudding user response：

You can use a for loop:

def square(i):
    return i ** 2


lst = [1,2,3,4,...]
for i in lst:
    result = square(i)
    print(result)

This works because the iterator, i goes through every element in lst and passes it as a parameter into our function, square().

I hope this helped! Let me know if you need any further clarification or details :)

CodePudding user response：

Use for loop.

yourlist = [1,2,3,4...]
for i in yourlist:
    yourfunction(i)

CodePudding user response：

def square(num):
        return num ** 2
lt = [1..n]
for i in lt:
        newElement = square(i)
        print(newElement)

You can use this or you can append the new element in a new list and print the list of square of original list.

nlist = []
for i in list:
      newEle = square(i)
      nlist.append(newEle)
 
print(nlist)

You can do it by both ways.