Check which number nearest to the value 0 among two given integers-CodePudding

I have 2 integers:

int number1 = 45;
int number2 = 40;

Now I want to compare both and check which one is nearer to the number 0.

As output I want true / false.

For example:

if (compare(number1, number2))
{
    console.write("number1 is nearer to 0");
}
else
{
    console.write("number2 is nearer to 0");
}

Output:

number 2 is nearer to 0

CodePudding user response：

You shold use ABS, before compare.

CodePudding user response：

int compare(int a, int b)  {
    if (abs(a) > abs(b)){
        std::cout <<b <<" is closer to zero" <<std::endl ;
        return b;
    }
    else{
        std::cout <<a <<" is closer to zero" <<std::endl ;
        return a;
    }
}

This function might be helpful for you. It both displays the answer in the terminal and returns the int value which is closer to 0 in order to be used by other parts of your program.

CodePudding user response：

I'm assuming you want the actual function 'compare', and that the integers can be negative

int compare(int number1, int number2) {
    return abs(number1) < abs(number2);
}