How to increment index in Python loop-CodePudding

I am wanting to loop through a string and capture 2 items each time while also incrementing through the index of the iterable. So I want to slice 2 items but increase the index by 1 every time through the loop. How can I do this?

my_string = 'teststring'

desired output = te es st ts st tr ri in ng

I have tried the following to slice the two items, but can't figure out the best way to iterate thought the index

str1 = 'teststring'
i=0
while i<10: 
    i  =1
    str2=str1[0:2]
    print(str2)

CodePudding user response：

Here is a possible solution (s is your string):

for j in range(len(s) - 1):
    print(s[j:j   2])

Another one:

for c1, c2 in zip(s[:-1], s[1:]):
    print(c1   c2)

CodePudding user response：

str1 = 'teststring'
result = []
for i in range(len(str1) - 1):
    result.append(str1[i:i   2])

print(result)

output

['te', 'es', 'st', 'ts', 'st', 'tr', 'ri', 'in', 'ng']

CodePudding user response：

By using list comprehension you can do this in a one-liner

s = 'teststring'

r = ' '.join([s[i:i 2] for i in range(len(s)-1)])

print(r)

CodePudding user response：

Since you are trying to move both the start and end point of the slice with each iteration, you want to use the index length of slice for the end point.

You should iterate after the slice is done. Here is the answer with minimal changes to your code:

str1 = 'teststring'
i=0
while i<=len(str1)-2: 
    str2=str1[i:i 2]
    i  = 1
    print(str2)

CodePudding user response：

I would use a for loop instead of a while loop, like this:

def strangeSlice(string):
    out = ""
    for i in range(len(string)-1):
        out  = string[i:i 2]
        if i != len(string)-2:
            out  = " "
    print(out)
    return out
def main():
    strangeSlice("teststring")