How to click on link where there is image in front in python using webdriver?-CodePudding

I am trying to click on the link behind the image on eBay.

Code

from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains
from selenium.webdriver.common.by import By
import time
url='https://www.ebay.com/sch/i.html?_from=R40&_nkw=Pet Sim X 1B 25B 100B 250B Gems/diamonds Pet Simulator X Cheep+Instant Delivery&_sacat=0&_fcid=1'
driver = webdriver.Chrome("E:\chromedriver.exe")
driver.maximize_window()
driver.minimize_window()
driver.maximize_window()
time.sleep(2)
driver.get(url)
#Gets all the elements of images on page
titles=driver.find_elements(By.XPATH,'//img[@]')
time.sleep(2)
#gets the element of first image
element=titles[0]
#clicks
ActionChains(driver).move_to_element(element).click().perform()
time.sleep(10)
driver.close()

So what it does is collects all elements of the image in a list and then I can click any specific element/IMG by just giving list index

URL

I can't click the image it should open a new tab but it doesn't please help me. Thank You

CodePudding user response：

The XPath locator you are using here is not good enough.
Instead of

titles=driver.find_elements(By.XPATH,'//img[@]')

Please use

titles=driver.find_elements(By.XPATH,'//div[@id="srp-river-results"]//img[@]')

This will give you correct results.
You should also remove the redundant driver.maximize_window() and use Expected Conditions explicit waits instead of hardcoded pauses like time.sleep(2)

CodePudding user response：

I see only one image in the link: Snapshot and for this, you can use this:

driver.get("https://www.ebay.com/sch/i.html?_from=R40&_nkw=Pet Sim X 1B 25B 100B 250B Gems/diamonds Pet Simulator X Cheep+Instant Delivery&_sacat=0&_fcid=1")
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH,'(//img[@])[2]'))).click()