If the integer pointed to by num begins with or contains 3

please tell me how to code this

CodePudding user response：

You can try converting the number to a string and then check, like this

some_num = 34566
# str(some_num) return the number in string i.e returns '34566'
if (len(str(some_num)) > 0 and ('3' in str(some_num)): print(True)