I need help with mongodb query. I have documents containing field url. For example:
{
_id: 123,
url: https://some-url.com/category/v1/12345.jpg
}
I have to update url in each doc. I have to replace the url, but the image part. It should like this:
https://anothe-url.com/some-new-cat/v2/12345.jpg
How can I achieve this?
CodePudding user response:
Regular expressions are usually slow. I would suggest this:
url = "https://some-url.com/category/v1/12345.jpg"
"https://anothe-url.com/some-new-cat/v2/" url.split("/").pop()