In TypeScript what is the idiomatic way to filter an array of strings with a regular expression AND-CodePudding

My input input is an array of strings lines. I would like to write code like the following in TypeScript.

lines
  .filter((line:string) => line.match(/resource "[^"] "/))
  .map((line:string) => line.match(/resource "([^"] "/)[1])

Frankly, I'm a little lost on how to accomplish this in TypeScript, and these are some of the reasons.

I know that at runtime the second match won't be null and will have captured something into slot [1], but the TypeScript compiler can't seem to figure this out and nags me.
I'm able to work around it with a second map operation that uses a ternary operator ? to check for null or empty arrays, and that actually compiles and runs fine. But the, the linter complains in a Git pre-commit hook, which tells me I'm on the wrong track.

What is the right track? What is the "correct" way to do this in TypeScript? Thanks!

CodePudding user response：

Match all the strings first, using optional chaining for brevity, then filter later by whether there was a match or not.

const matches = lines
    .map(line => line.match(/resource "([^"] ")/)?.[1])
    .filter(Boolean) as string[];

But your matching of /resource "([^"] "/ looks a bit suspicious - did you really want to exclude the first " and include the second? Or might you have wanted /resource "([^"] )"/?