Extract keywords from links-CodePudding

I'm trying to extract the first 2 numbers in links like these:

https://primer.text.com/sdfg/8406758680-345386743-DSS1-S JasdOdsfrIwetds-Osdgf/ 
https://primer.text.com/sdfg/8945879094-849328844-DPE-S JsdfeOIert-Isdfu/
https://primer.text.com/sdfg/8493093053-292494834-QW23#Wsdfg#IprfdUiojn2Asdfg-Werts/

The output should be like this:

id1 = ['8406758680', '8945879094','8493093053']
id2 = ['345386743', '849328844', '292494834']

I'm trying to do this using the re module.

Please, tell me how to do it.

This the code snippet I have so far:

def GetUrlClassId(UrlInPut):
    ClassID = ''
    for i in UrlInPut:
        if i.isdigit():
            ClassID =i
        elif ClassID !='':
            return int(ClassID)
    return ""

def GetUrlInstanceID(UrlInPut):
    InstanceId = ''
    ClassID = 0
    for i in UrlInPut:
        if i.isdigit() and ClassID==1:
            InstanceId =i
        elif InstanceId !='':
            return int(InstanceId)
        if i == '-':
            ClassID =1
    return ""

I don't want to use something like this. I would like to use regular expressions.

CodePudding user response：

The regex pattern: /(\d{10})-(\d{9}) the brackets are needed to identify the groups of digits, the {} specifies an exact occurrence of a repetition, doc.

# urls separated by a white space
urls = 'https://primer.text.com/sdfg/8406758680-345386743-DSS1-S JasdOdsfrIwetds-Osdgf/ https://primer.text.com/sdfg/8945879094-849328844-DPE-S JsdfeOIert-Isdfu/ https://primer.text.com/sdfg/8493093053-292494834-QW23#Wsdfg#IprfdUiojn2Asdfg-Werts/'

urls = urls.split() # as list

import re

ids = [re.search(r'/(\d{10})-(\d{9})', url).groups() for url in urls]
print(list(zip(*ids)))

Output

[('8406758680', '8945879094', '8493093053'), ('345386743', '849328844', '292494834')]

CodePudding user response：

With Regex, you can do a literal match on the base URL, and then capture two groups of multiple digits using \d (\d matches 0-9, matches at least one of the proceeding group). re.findall returns a list of matching groups.

import re
l1 = "https://primer.text.com/sdfg/8406758680-345386743-DSS1-S JasdOdsfrIwetds-Osdgf/"
l2 = "https://primer.text.com/sdfg/8945879094-849328844-DPE-S JsdfeOIert-Isdfu/"
l3 = "https://primer.text.com/sdfg/8493093053-292494834-QW23#Wsdfg#IprfdUiojn2Asdfg-Werts/"

for l in [l1, l2, l3]:
  result = re.findall(r'https://primer.text.com/sdfg/(\d )-(\d )', l)
  print(result)

Output:

[('8406758680', '345386743')]
[('8945879094', '849328844')]
[('8493093053', '292494834')]

From here, reformatting into your desired data structure should be simple enough (use zip or something).