I want to create a folder named after a specific name using python-CodePudding

I want to create a folder named after a specific name. Like in the picture (a folder with only numbers except for .zip).

here is my code.

import os
import glob
import zipfile
import sys


p_dir =  './data/'

for file in os.listdir(p_dir):
    file_name = file
    oldname = str(file_name)
    newname1 = file.split('_')[5]   '.zip'
    newname = str(newname1)
    os.rename(os.path.join(p_dir, oldname), os.path.join(p_dir, newname))
    os.makedirs(p_dir, newname1)

but error is.. TypeError: an integer is required (got type str) What should I do?

CodePudding user response：

The immediate error is that your makedirs invocation is wrong. If you pass in two arguments, the second argument should be a number which indicates the permissions of the directory; for example, 0o751 (decimal 489) indicates read write execute (7) for owner, read execute (5) for group, and execute (1) for others. (Conventionally, these numbers are communicated in octal, because they map nicely to one digit per permission.)

However, you are also needlessly converting variables which are already strings to strings, and copying things which don't need to be copied.

It's also not clear why you split on _; your example image shows no file names with underscores in them, let alone then file names with five or more of them. Per your problem description, I'm guessing you want to look for a .zip extension and remove it.

Try this:

import os
# import glob     # unused
# import zipfile  # unused
# import sys      # unused


p_dir =  './data/'

for file in os.listdir(p_dir):
    if file.endswith('.zip'):
        newname = file[:-4]
        os.makedirs(os.path.join(p_dir, newname))

CodePudding user response：

as per your code

newname1 = file.split('_')[5]   '.zip'
newname = str(newname1)

newname1 and newname are the same

as per your code

os.makedirs(p_dir, newname1)

This is wrong code

You need to write

os.makedirs(os.path.join(p_dir, newname1))

But still you will get an error

There fore you need to remove .zip for newname1

may be like below

newname1 = file.split('_')[5]
newname = str(newname1)   '.zip'

So your final code will look like

import os
import glob
import zipfile
import sys


p_dir =  './data/'

for file in os.listdir(p_dir):
    file_name = file
    oldname = str(file_name)
    print(file)
    newname1 = file.split('_')[5]
    newname = str(newname1)   '.zip'
    os.rename(os.path.join(p_dir, oldname), 
    os.path.join(p_dir, newname))
    os.makedirs(os.path.join(p_dir, newname1))

But I don't understand the _ split

CodePudding user response：

In os.makedirs(path[, mode]) you can pass two parameters. path and mode(optional) and the error you get is because the mode should be an integer. And the default mode is Oo777 in octal. Therefore you can use the following code to fix your problem.

import os
p_dir = './data'

for file in os.listdir(p_dir):
   newname = file[:-4]
   os.makedirs(os.path.join(p_dir, newname))

import os
p_dir = './data'

for file in os.listdir(p_dir):
   newname = file[:-4]
   os.makedirs(os.path.join(p_dir, newname), 0o777))