I am a beginner(ish) with Python and having trouble with getting the correct syntax for this. Any help is greatly appreciated!
I have a dictionary and a list of tuples. I would like to compare the key of my dictionary to a value in the tuple, and if meets criteria return a different tuple value. Here's the illustration:
dictionary = {datetime.datetime(2022, 4, 12, 9, 30): 30, datetime.datetime(2022, 4, 12, 11, 0): 60, datetime.datetime(2022, 4, 12, 13, 0): 30}
tuplelist = [(1, datetime.time(6, 45, 21)), (2, datetime.time(7, 15, 21)), (3, datetime.time(7, 45, 21)...etc)
The goal is to see which increment of 30 minutes my dictionary key falls into, and update it with the increment number stored in tuple list. What I tried:
for k,y in dictionary:
for i, t in tuplelist:
if t <= k <= (t datetime.timedelta(minutes = 30)):
dictionary[k] = t
The error I got is unable to unpack non iterable type datetime.
Any help and/or explanation is welcome! I am really enjoying learning to code but not from a CS background so always looking for the how it works in addition to just the correct syntax.
Thank you!
Update for working solution:
newdic = {}
for k,v in dictionary.items():
for item in mylist:
i, t = item
if t <= k.time() <= (datetime.combine(datetime.today(),t) datetime.timedelta(minutes=30)).time():
newdic.update({i : v})
else:
continue
CodePudding user response:
This is not the complete answer. See if it helps resolve early issues up to the comment.
import datetime
dictionary = {datetime.datetime(2022, 4, 12, 9, 30): 30,
datetime.datetime(2022, 4, 12, 11, 0): 60,
datetime.datetime(2022, 4, 12, 13, 0): 30}
tuplelist = [(1, datetime.time(6, 45, 21)), (2, datetime.time(7, 15, 21)),
(3, datetime.time(7, 45, 21),)]
for k, y in dictionary.items():
for item in tuplelist: # get each tuple from the list
i, t = item # unpack the tuple into i and t
print(f'{i=} {t=}') # Check i and t values
# if t <= k <= (t datetime.timedelta(minutes=30)):
# dictionary[k] = t