Python remove tuples and merge the two values from tuples inside them to one item-CodePudding

I have list similar to this:

[('name', ''),('season', ''),('company', ''),('date', ''),('mean value', 1),('mean value', 2),('mean value', 3), ('mean value', 4)]

I would like to get rid of the tuples and to merge between the two values if exists, to get the following list:

['name','season','company','date','mean value 1','mean value 2', 'mean value 3', 'mean value 4']

I'm not sure how to do this, looking for ways to do this efficiently.

CodePudding user response：

If you want to add in a space (mean value 4):

[f"{a} {b}".strip() for a, b in lst]

If you don't need a space ('mean value4'):

[f"{a}{b}" for a, b in lst]

Note: This answer only works for tuples of length 2

CodePudding user response：

list(map(lambda t: " ".join(map(lambda x: str(x), t)), mylist))

[" ".join(map(lambda x: str(x), t)) for t in mylist]

CodePudding user response：

I think this code is easy to understand and works.

tup = [('name', ''),('season', ''),('company', ''),('date', ''),('mean value', 1),('mean value', 2),('mean value', 3), ('mean value', 4)]

def func(value):
    string = ''
    for a in value:
        string  = str(a)
        string =' '
    return string.strip()
result = list(map(func,tup))

CodePudding user response：

How about if-else in a list comprehension

stuff = [('name', ''),('season', ''),('company', ''),('date', ''),('mean value', 1),('mean value', 2),('mean value', 3), ('mean value', 4)]

joined = [f'{a} {b}' if b else a for a, b in stuff]
print(joined)

CodePudding user response：

Check this:

test_list = [('name', ''),('season', ''),('company', ''),('date', ''),('mean value', 1),('mean value', 2),('mean value', 3), ('mean value', 4)]
new_list = []
for item in test_list:
    new_list.append(' '.join(map(str,item)).strip())