How to click on the play button with selenuim python-CodePudding

I'm trying to click the play button on this website

Here is my code below

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.common.exceptions import NoSuchElementException
import time

browser = webdriver.Chrome()
browser.get("https://audiomack.com/iamrealtraffic")
time.sleep(10)
a = driver.find_element_by_xpath('//path[@d="M70.79 103c-.988 0-1.79-.802-1.79-1.79V69.866c0-.99.802-1.79 1.79-1.79l29.104 16.118s1.344 1.343 0 2.686C98.55 88.225 70.79 103 70.79 103"]')
webdriver.ActionChains(browser).move_to_element(a).click(a).perform()

CodePudding user response：

Are you sure you have the right xpath? I would try this xpath:

/html/body/div[2]/div[3]/div/div[2]/div[1]/div/div/div/div/div/div[2]/div/div/span[1]/button

Also I would use implicitlywait instead of time.sleep.

CodePudding user response：

To click on the play icon you need to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following locator strategies:

Using CSS_SELECTOR:

driver.get("https://audiomack.com/black-sherif/song/kweku-the-traveler")
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "div.row button[data-action='play']"))).click()

Using XPATH:

driver.get("https://audiomack.com/black-sherif/song/kweku-the-traveler")
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//div[@class='row']//button[@data-action='play']"))).click()

Note: You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC