I am refering this answer to parse url but when parse this url
NSString *urlString = @"https://www.example.com/product-detail?journey_id=123456&iswa=1";
I am getting my 1st key is https://www.example.com/product-detail?journey_id
But I need only journey_id
as my key.
This is what I have done in coding:
NSString *urlString = @"https://www.example.com/product-detail?journey_id=123456&iswa=1";
NSMutableDictionary *waLoginDictionary = [[NSMutableDictionary alloc] init];
NSArray *urlComponents = [urlString componentsSeparatedByString:@"&"];
for (NSString *keyValuePair in urlComponents) {
NSArray *pairComponents = [keyValuePair componentsSeparatedByString:@"="];
NSString *key = [[pairComponents firstObject] stringByRemovingPercentEncoding];
NSString *value = [[pairComponents lastObject] stringByRemovingPercentEncoding];
[waLoginDictionary setObject:value forKey:key];
}
NSLog(@"%@", waLoginDictionary);
I am getting This output:
{
"https://www.example.com/product-detail?journey_id" = 123456;
iswa = 1;
}
CodePudding user response:
The answer you are referring to is outdated and has been updated accordingly by the writer himself. Apple added [URLQueryItem]
in the URLComponent
object.
Try this.
Swift
let urlString = "https://www.example.com/product-detail?journey_id=123456&iswa=1"
var dict: [String : String] = [:]
if let urlComponents = URLComponents(string: urlString), let queryItems = urlComponents.queryItems {
for item in queryItems {
dict[item.name] = item.value
}
}
print("dict : \(dict)")
Objective - C
NSString *urlString = @"https://www.example.com/product-detail?journey_id=123456&iswa=1";
NSMutableDictionary *dict = [NSMutableDictionary dictionary];
NSURLComponents *urlComponents = [NSURLComponents componentsWithString:urlString];
NSArray *queryItems = [urlComponents queryItems];
for (NSURLQueryItem *item in queryItems) {
[dict setValue:item.value forKey:item.name];
}
NSLog(@"dict %@", dict);