Private void btnLogin_Click (object sender, EventArgs e)
{
If (txtUser. Text. The ToString ()=="123456" & amp; & TxtPassword. Text. The ToString ()=="123456")
{
This. Hide ();
ManagementForm eManagementForm=new ManagementForm ();
EManagementForm. ShowDialog ();
Enclosing the Close ();
}
The else
{
MessageBox. Show (" the user name or password error!" );
}

CodePudding user response:

Problem description specific again, whether want to put the user name and password are passed to the second window? The simplest way is to change the window 2 Modifier in the text box attributes to public, you can directly call:
EManagementForm. TxtUserName=this. TxtUser. Text;
EManagementForm. TxtUserPwd=this. TxtPassword. Text;
EManagementForm. ShowDialog ();

CodePudding user response:

reference 1st floor datafansbj response:

problem description specific again, whether want to put the user name and password are passed to the second window? The simplest way is to change the window 2 Modifier in the text box attributes to public, you can directly call:
EManagementForm. TxtUserName=this. TxtUser. Text;
EManagementForm. TxtUserPwd=this. TxtPassword. Text;
EManagementForm. ShowDialog ();

Is to modify the previous password in the second window

CodePudding user response:

The code above spelling has a problem, there is no validated, principle is no problem, should be changed to the following:
EManagementForm. TxtUserName. Text=this. TxtUser. Text;
EManagementForm. TxtUserPwd1. Text=this. TxtPassword. Text;
EManagementForm. TxtUserPwd2. Text=this. TxtPassword. Text;
EManagementForm. ShowDialog ();