Convert zip lists to a txt file without using any libraries-CodePudding

for (a, b, c, d, e, f, g) in zip(A, B, C, D, E, F, G):
    result = ''.join([a,b,c,d,e,f,g])

# Write the file
with open("file.txt","w") as f:
    f.write(result)

This only gives one line instead of the whole result. The type of the result is shown below. May I know how to convert the whole result to a txt file? Thanks a lot.

<class 'str'>

<class 'str'>

<class 'str'>

<class 'str'>

<class 'str'>

<class 'str'>

<class 'str'>

<class 'str'>

<class 'str'>

<class 'str'>

<class 'str'>

CodePudding user response：

You need to call f.write(result) in the loop. And append a newline to each line.

with open("file.txt","w") as f:
    for data in zip(A, B, C, D, E, F, G):
        result = ''.join(data)
        f.write(result   '\n')

There's no need to spread the zipped tuples into variables if you're just going to combine them back into a list. Just use the tuples directly.

CodePudding user response：

This is all happens because the value of result is assign to the last value.

result = []
for (a, b, c, d, e, f, g) in zip(A, B, C, D, E, F, G):
    result.append(''.join([a,b,c,d,e,f,g]) '\n')

# Write the file
with open("file.txt","w") as f:
    f.writelines(result)