O baidu30data/sum (baidu30data)
CodePudding user response:
MY SQL does not support partition by rangeYou can use the following
Select *, a. aidu30data/b.a from a TB as a
INNER join (select sum (baidu30data) as aa from TB) b on 1=1;
CodePudding user response:
The subquery.CodePudding user response:
1/f, positive solution! Thank smecta.CodePudding user response:
The select clause also can directly use the subquery,CodePudding user response:
Select *, a. aidu30data/(select sum (baidu30data) from TB) a.a from TB as a a