Does GCC (or alternatively Clang) defines any macro when it is compiled for the Arch Linux OS?
I need to check that my software restricts itself from compiling under anything but Arch Linux (the reason behind this is off-topic). I couldn't find any relevant resources on the internet.
Does anyone know how to guarantee through GCC preprocessor directives that my binaries are only compilable under Arch Linux?
Of course I can always
#ifdef __linux__
...
#endif
But this is not precise enough.
Edit: This must be done through C source code and not by any building systems, so, for example, doing this through CMake is completely discarded.
Edit 2: Users faking this behaviour is not a problem since the software is distributed to selected clients and thus, actively trying to "misuse" our source code is "their decision".
CodePudding user response：
Does GCC (or alternatively Clang) defines any macro when it is compiled for the Arch Linux OS?
No. Because there's nothing inherently specific to Arch Linux on the binary level. For what it's worth, when compiling the only things you/the compiler has to care about is the target architecture (i.e. what kind of CPU it's going to run with), data type sizes and alignments and function calling conventions.
Then later on, when it's time to link the compiled translation unit objects into the final binary executable, the runtime libraries around are also of concern. Without taking special precautions you're essentially locking yourself into the specific brand of runtime libraries (glibc vs. e.g. musl; libstdc vs. libc ) pulled by the linker.
One can easily sidestep the later problem by linking statically, but that limits the range of system and midlevel APIs available to the program. For example on Linux a purely naively statically linked program wouldn't be able to use graphics acceleration APIs like OpenGL-3.x or Vulkan, since those rely on loading components of the GPU drivers into the process. You can however still use X11 and indirect GLX OpenGL, since those work using wire protocols going over sockets, which are implemented using direct syscalls to the kernel.
And these kernel syscalls are exactly the same on the binary level for each and every Linux kernel of every distribution out there. Although inside of the kernel there's a lot of leeway when it comes to redefining interfaces, when it comes to the interfaces toward the userland (i.e. regular programs) there's this holy, dogmatic, ironclad rule that YOU NEVER BREAK USERLAND! Kernel developers breaking this rule, intentionally or not are chewed out publicly by Linus Torvalds in his in-/famous rants.
The bottom line to this is, that there is no such thing as a "Linux distribution specific identifier on the binary level". At the end of the day, a Linux distribution is just that: A distribution of stuff. That means someone or more decided on a set of files that make up a working Linux system, wrap it up somehow and slap a name on it. That's it. There's nothing inherently specific to "Arch" Linux other than it's called "Arch" and (for the time being) relies on the pacman package manager. That's it. Everything else about "Arch", or any other Linux distribution, is just a matter of happenstance.
If you really want to sort different Linux distributions into certain bins regarding binary compatibility, then you'd have to pigeonhole the combinations of
Minimum required set of supported syscalls. This translates into minimum required kernel version.
What libc variant is being used; and potentially which version, although it's perfectly possible to link against a minimally supported set of functions, that has been around for almost "forever".
What variant of the C standard library the distribution decided upon. This actually also inflicts programs that might appear to be purely C, because certain system level libraries (*cough* Mesa *cough*) will internally pull a lot of C infrastructure (even compilers), also triggering other "fun" problems¹
I need to check that my software restricts itself from running under anything but Arch Linux (the reason behind this is off-topic). I couldn't find any relevant resources on the internet.
You couldn't find resources on the Internet, because there's nothing specific on the binary level that makes "Arch" Arch. For what it's worth right now, this instant I could create a fork of Arch, change out its choice of default XDG skeleton – so that by default user directories are populated with subdirs called leech, flicks, beats, pics – and call it "l33tz" Linux. For all intents and purposes it's no longer Arch. It does behave significantly different from the default Arch behavior, which would also be of concern to you, if you'd relied on any specific thing, and be it most minute.
Your employer doesn't seem to understand what Linux is or what distinguished distributions from each other.
Hint: It's not the binary compatibility. As a matter of fact, as long as you stay within the boring old realm of boring old glibc libstdc Linux distributions are shockingly compatible with each other. There might be slight differences in where they put libraries other than libc.so, libdl.so and ld-linux[-${arch}].so, but those two usually always can be found under /lib. And once ld-linux[-${arch}].so and libdl.so take over (that means pulling in all libraries loaded at runtime) all the specifics of where shared objects and libraries are to be found are abstracted away by the dynamic linker.
1: like becoming multithreaded only after global constructors were executed and libstdc deciding it wants to be singlethreaded, because libpthread wasn't linked into a program that didn't create a single thread on its own. That was a really weird bug I unearthed, but yshui finally understood https://gitlab.freedesktop.org/mesa/mesa/-/issues/3199
CodePudding user response：
No, it doesn't. And even if it did, it wouldn't stop anyone from compiling the code on an Arch Linux distro and then running it on a different Linux.
If you need to prevent your software from "from running under anything but Arch Linux", you'll need to insert a run-time check. Although, to be honest, I have no idea what that check might consist of, since linux distros are not monolithic products. The actual check would probably have to do with your reasons for imposing the restriction.
CodePudding user response：
You can list the predefined preprocessor macros with
gcc -dM -E - /dev/null
clang -dM -E - /dev/null
None of those indicate what operating system the compiler is running under. So not only you can't tell whether the program is compiled under Arch Linux, you can't even tell whether the program is compiled under Linux. The macros __linux__ and friends indicate that the program is being compiler for Linux. They are defined when cross-compiling from another system to Linux, and not defined when cross-compiling from Linux to another system.
You can artificially make your program more difficult to compile by specifying absolute paths for system headers and relying on non-portable headers (e.g. /usr/include/bits/foo.h). That can make cross-compilation or compilation for anything other than Linux practically impossible without modifying the source code. However, most Linux distributions install headers in the same location, so you're unlikely to pinpoint a specific distribution.
You're very likely asking the wrong question. Instead of asking how to restrict compilation to Arch Linux, start from why you want to restrict compilation to Arch Linux. If the answer is “because the resulting program wouldn't be what I want under another distribution”, then start from there and make sure that the difference results in a compilation error rather than incorrect execution. If the answer to “why” is something else, then you're probably looking for a technical solution to a social problem, and that rarely ends well.