I want to make a button that will create a back page
if I click this it will return to the last div content. I already have the function for the next page but I'm already ran out of logic for making a function for the back page
button.
Here is my code for the content and my function for the next()
function next() {
if ($('#content1').hasClass('')) {
$('#content2').removeClass('hidden');
$('#back').removeClass('hidden');
$('#content1').addClass('hidden');
} else if ($('#content2').hasClass('')) {
$('#content2').addClass('hidden');
$('#content3').removeClass('hidden');
} else if ($('#content3').hasClass('')) {
$('#content3').addClass('hidden');
$('#content4').removeClass('hidden');
} else if ($('#content4').hasClass('')) {
$('#content4').addClass('hidden');
$('#content5').removeClass('hidden');
}
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js"></script>
<div >
<div id="content1">
<h1>1</h1>
</div>
<div id="content2" >
<h1>2</h1>
</div>
<div id="content3" >
<h1>3</h1>
</div>
<div id="content4" >
<h1>4</h1>
</div>
<div id="content5" >
<h1>5</h1>
</div>
<button onclick='next()'>Next Page</button>
<button id="back" onclick='back()' >Back Page</button>
</div>
CodePudding user response:
You can simplify this.
Here I remove the inline functions and have only one function.
Also no need for classes.
$(function() {
$container = $("div.myDiv");
$contents = $(".myDiv > div");
$(".nav").on("click", function() {
const next = $(this).is("#next"); // we clicked next
let $cur = $container.find("div:visible"); // currently visible
let $show = next ? $cur.next() : $cur.prev(); // next or prev div?
$("#next").toggle($show.index() < $contents.length - 1);
$("#prev").toggle($show.index() >= 1);
$cur.hide();
$show.show();
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js"></script>
<div >
<div id="content1">
<h1>1</h1>
</div>
<div id="content2" hidden>
<h1>2</h1>
</div>
<div id="content3" hidden>
<h1>3</h1>
</div>
<div id="content4" hidden>
<h1>4</h1>
</div>
<div id="content5" hidden>
<h1>5</h1>
</div>
<button id="prev" hidden>Previous Page</button>
<button id="next">Next Page</button>
</div>
CodePudding user response:
You could do it like this:
function next() {
var div = $("div[id^=content]:visible")
var nextdiv = div.next("[id^=content]");
if (nextdiv) {
div.addClass("hidden");
nextdiv.removeClass("hidden");
$("#back").show();
$('#next').toggle(nextdiv.next("[id^=content]").length > 0)
}
}
function back() {
var div = $("div[id^=content]:visible")
var prevdiv = div.prev("[id^=content]");
if (prevdiv) {
div.addClass("hidden");
prevdiv.removeClass("hidden");
$("#next").show();
$('#back').toggle(prevdiv.prev("[id^=content]").length > 0)
}
}
This will make it more dynamic and easier to manage.
One thing i use here is the [id^=content]
selector. That means it will only select elements where the id starts with content
.
function next() {
var div = $("div[id^=content]:visible")
var nextdiv = div.next("[id^=content]");
if (nextdiv) {
div.addClass("hidden");
nextdiv.removeClass("hidden");
$("#back").show();
$('#next').toggle(nextdiv.next("[id^=content]").length > 0)
}
}
function back() {
var div = $("div[id^=content]:visible")
var prevdiv = div.prev("[id^=content]");
if (prevdiv) {
div.addClass("hidden");
prevdiv.removeClass("hidden");
$("#next").show();
$('#back').toggle(prevdiv.prev("[id^=content]").length > 0)
}
}
.hidden {
display: none
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div >
<div id="content1">
<h1>1</h1>
</div>
<div id="content2" >
<h1>2</h1>
</div>
<div id="content3" >
<h1>3</h1>
</div>
<div id="content4" >
<h1>4</h1>
</div>
<div id="content5" >
<h1>5</h1>
</div>
<button id="next" onclick='next()'>Next Page</button>
<button id="back" onclick='back()' >Back Page</button>
</div>