How do you remove each row after each "close_condition" == 1 until you reach a "open_condition" == 1 row?
No row with "open_condition" == 1 is to be deleted
open_condition close_condition
0 1 1
1 0 1
2 0 0
3 0 0
4 0 1
5 0 1
6 1 0
7 1 0
8 1 1
9 0 0
10 1 0
11 1 0
12 0 0
13 1 0
14 0 0
15 0 0
16 1 0
17 0 0
18 1 1
19 0 1
should become
open_condition close_condition
0 1 1
6 1 0
7 1 0
8 1 1
10 1 0
11 1 0
12 0 0
13 1 0
14 0 0
15 0 0
16 1 0
17 0 0
18 1 1
CodePudding user response：
You could create a "running close flag" that resets to 0 every time it encounters an open_condition
df['rcf'] = [c if o else np.nan for (o, c) in zip(df['open_condition'], df['close_condition'])]
df['rcf'] = df['rcf'].fillna(method='ffill').astype('int')
df['keep'] = (df['open_condition'] (1 - df['rcf'])).astype(bool)
df[df['keep']]
Output
open_condition close_condition rcf keep
0 1 1 1 True
6 1 0 0 True
7 1 0 0 True
8 1 1 1 True
10 1 0 0 True
11 1 0 0 True
12 0 0 0 True
13 1 0 0 True
14 0 0 0 True
15 0 0 0 True
16 1 0 0 True
17 0 0 0 True
18 1 1 1 True