How to create a keyboard from tkinter buttons that stores the entered letter?-CodePudding

I am writing a python hangman code with tkinter interactive window, which includes a keyboard. I have created the keyboard, however I cannot figure out how to find out which keyboard key was pressed by the user and how to store it as a letter in a variable. I will be really grateful for any help!

klavesnice = Tk()
klavesnice.geometry("800x700 120 100")
buttons = []  
buttons = [
        'q','w','e','r','t','y','u','i','o','p',
        'a','s','d','f','g','h','j','k','l',
        'z','x','c','v','b','n','m'
    ]

radek=3 #row
sloupec=0 #collumn

for button in buttons:
    command=lambda  x=button: select(x)
    if button!='Space':
        Button(klavesnice,text=button,width=5,font=("arial",14,"bold"),bg='powder blue',command=command,padx=3.5,pady=3.5,bd=5).grid(row=radek,column=sloupec)
    if button=='Space':
        Button(klavesnice,text=button,command=command).grid(row=5,column=sloupec)
    sloupec =1
    #určení rozložení klávesnice
    if sloupec>9 and radek==3:
        sloupec=0
        radek =1
    if sloupec>8 and radek==4:
        sloupec=0
        radek =1

The code above is what displays the keyboard and the code below is the only thing I was able to come up with, which does not save the clicked key to a variable.

zadane=""
entry=Text(zadane_rm,width=43,height=3)
entry.grid(row=1,columnspan=40)
def select(value):
    if value=='Space':
        entry.insert(END,'')
    else:
        entry.insert(END, value)

I would like to store the clicked letter in a string variable called zadane.

CodePudding user response：

To do what you want only requires modifying the select() function so it appends the current value argument to the global zadane string variable. Note I have reformatted your code to follow the PEP 8 - Style Guide for Python Code guideline more closely to make it more readable.

import tkinter as tk  # Avoid `import *`

klavesnice = tk.Tk()
klavesnice.geometry("800x700 120 100")

buttons = [
    'q','w','e','r','t','y','u','i','o','p',
    'a','s','d','f','g','h','j','k','l',
    'z','x','c','v','b','n','m'
]

zadane = ''
entry = tk.Text(klavesnice, width=43, height=3)
entry.grid(row=1, columnspan=40)

def select(value):
    global zadane
    if value=='Space':
        entry.insert('end', '')
    else:
        entry.insert('end', value)
        zadane = zadane   value
        print(f'{zadane=!r}')


radek = 3 #row
sloupec = 0 #collumn

for button in buttons:
    command = lambda x=button: select(x)
    if button != 'Space':
        tk.Button(klavesnice, text=button, width=5, font=("arial", 14, "bold"),
                  bg='powder blue', command=command, padx=3.5, pady=3.5, bd=5
                 ).grid(row=radek, column=sloupec)
    if button == 'Space':
        tk.Button(klavesnice, text=button, command=command).grid(row=5, column=sloupec)
    sloupec  = 1
    # Specify the keyboard layout
    if sloupec > 9 and radek == 3:
        sloupec = 0
        radek  = 1
    if sloupec > 8 and radek == 4:
        sloupec = 0
        radek  = 1

klavesnice.mainloop()

CodePudding user response：

That might be dumb but why not just adding the letter that is pressed to an array ? And every time you press a letter it will check if it is in the array ?