I've Created a view

urlpatterns = [
   path('book/<suffix>/', views.bookview, name='bookDetail')`
]

what i want

• if someone hits url '127.0.0.1:8000/book/1/2/3/4/5/6/'
• i do not want django to raise an error of The current path, book/1/2/3/4/5/6/, didn’t match any of these.
• but instead it shows the same view of url book/<suffix>/ which is view.bookview.
• and somehow pass, suffix after book/ which is 1/2/3/4/5/6/ as arg so that i can access it in my view.

CodePudding user response：

from django.urls import re_path

urlpatterns = [
    re_path(r'^book/(?P<suffix>[\w/] )$', views.bookview, name='bookDetail')
]

CodePudding user response：

As there can be special characters in the suffix parameter, you need to encode the string. In python you can do it like this

from urllib.parse import quote_plus
suffix = quote_plus('/1/2/3/4/5/6/')