Fill a list with 10 random numbers, then chose 5 of them randomly-CodePudding

I want to generate a list with 10 random floats using a loop. Afterwards I want to print 5 of these randomly.

I have this loop:

    import random
    for i in range(5):
        print(float(random.randint(1,10)

this gives me an output of 5 random numbers between 1-10. But is the result really random floats?

With this, I didn't really fill a list with 10 random floats did I?

    for a in range(1,11,1):
        print(a)

would this be better? As I understood, random.sample creates a list automatically. Is that true?

    import random
    a = random.sample(range(1,11),10)
    print(a)

there the output would be e.g.: [1, 3, 7, 6, 9, 10, 5, 8, 4, 2]

but then it would give me just 1-10 back in a random order.

So I could change range to range(1,1000),10)

Then it would create a list with 10 random numbers only within 1 to 1000.

Is there a solution to this? I am just curious, bc if its infinite then I likely get a 10 digit number which is way too long.

If I want to choose 5 random numbers from the randomly filled list I tried to use this code:

    import random
    a = random.sample(range(1,1000),10)

    for a in range(5):
        print(a)

but this gives me only that:

I know it has to be something about the range(5) but I assume that the loop doesn't choose the numbers from the list I created, am I right?

Can someone help me here?

CodePudding user response：

random.sample returns unique random elements - i.e. if you sample 10 elements from a list of 10 elements - all elements are guaranteed to be there

From the docs help(random.sample) -

sample(population, k) method of random.Random instance Chooses k unique random elements from a population sequence or set.

To sample with repetition, you can use the choices function -

From the docs - help(random.choices)

choices(population, weights=None, *, cum_weights=None, k=1) method of random.Random instance Return a k sized list of population elements chosen with replacement.

For example,

b = random.choices(range(1, 11), k=10)
print(b)
# [1, 10, 9, 8, 6, 1, 6, 4, 9, 3]