Go's documentation says that
Gosched yields the processor, allowing other goroutines to run. It does not suspend the current goroutine, so execution resumes automatically.
Based on that definition if I have a series of long running go routines being created and executed concurrently, would it be advantageous to write a select statement the following way:
for {
select {
case msg := <- msgch :
fmt.Println(msg)
default:
runtime.Gosched()
}
}
I assume based on the documentation, this code can result in more go routines being run. Is my assumption correct?
CodePudding user response:
No, it isn't necessary here, because whenever Go is waiting on a channel or waiting for I/O, it allows other goroutines to run automatically. That's been the case since Go 1.0.
In Go 1.2 the Go runtime's scheduler added automatic preemption points whenever you called a function. Prior to that if you had a CPU-bound loop (even with a function call) it could starve the scheduler and you might need runtime.Gosched
.
And then in Go 1.14, they made this aspect of the runtime even better, and even tight CPU-bound loops with no functions calls are automatically pre-empted.
So with any Go version, you don't need to call runtime.Gosched
when you're just waiting on a channel or on I/O; before 1.14, you may have wanted to call it if you were doing a long-running calculation. But with Go 1.14 , I don't see why you'd ever need to call it manually.
If I was reviewing your actual code, I'd suggest changing it to a simple for ... range
loop:
for msg := range msgCh {
fmt.Println(msg)
}
This will wait for each message to come in and print it, and stop if/when the channel is closed. However, you would want a switch
if you're waiting on another channel or done signal, for example a context. Something like this:
for {
select {
case msg := <- msgCh:
fmt.Println(msg)
case <-ctx.Done():
return
}
}
CodePudding user response:
Does using
runtime.Gosched()
[anywhere] make any sense?
No. It basically is never needed or sensible to use Gosched.