C: where should I place the while loop-CodePudding

I have an issue with my code. It works properly but I want it to start again after processing, but the program ends and the console closes. I think I need to use a while loop but I'm getting an error. Can you help me please.

here is my code

#include <stdio.h>
#include <math.h>
#include <conio.h>
int main(){
int x,y,tercih; // menu dizilimi sor, programın calismaya devam etmesi gerekiyor.
printf("___ MENU ___\n");
printf("1) Kare Kup\n");
printf("2) Ucgen Tetrahedron\n");
printf("3) Daire Kure\n");
printf("4) Gauss Dagilimi\n");
printf("5) Programdan cik\n");
printf("Lutfen yapmak istediginiz islemi seciniz: ");
scanf("%d",&tercih);
if (tercih==1){
printf("Lutfen kare ve kupun bir ayritinin uzunlugunu giriniz: ");
scanf("%f",&x);
printf("                 Alan   Hacim\nKare          %6.2f  %6.2f\nKup           %6.2f  %6.2f 
",x*x,0,6*(x*x),x*x*x); // sonuc 0.00 cikiyor?
} else if (tercih==2){
 printf("Lutfen ucgen ve tetrahedronun bir ayritinin uzunlugunu giriniz: ");
scanf("%d",&x);
printf("                 Alan   Hacim\nUcgen         %6.2f  %6.2f\nTetra         %6.2f  %6.2f 
",sqrt(3)/4*x*x,0,sqrt(3)*x*x,sqrt(2)/12*x*x*x);
} else if (tercih==3){
 printf("Lutfen daire ve kurenin yaricap uzunlugunu giriniz: ");
 scanf("%d",&x);
 printf("                 Alan   Hacim\nDaire          %6.2f  %6.2f\nKure            %6.2f  %6.2f ",M_PI*x*x,0,M_PI*x*x*x*4/3,4*M_PI*x*x); 
} else if (tercih==4){
 printf("Lutfen sirasiyla sapma ve boyut degerleri giriniz: "); // soruyu anla yada sor 
 scanf("%d %d",&x,&y);
 printf("Sonuc: %d",x/y);
 } else if (tercih==5){
 printf("Programdan cikiliyor. ");
} else {
 printf("Yanlis islem girdiniz!");
}
return 0;

CodePudding user response：

I believe the problem is not due to your program, but the way that you launch it: I have the impression that you double-click your program in your Windows explorer, your program opens a command prompt, runs, stops and closes the command prompt.

You can alter this, using a pause or a while-loop, but you might also simply start your program in another way: you open a command prompt (cmd) and your open your program in that prompt. Once your program is stopped, the command prompt won't be closed and you can read the output on screen.

P.s. a pause can be achieved using this C command:

getchar();

CodePudding user response：

In pulling your logic into a separate function, it becomes much more reasonable to deal with the actual menu operations, without having to worry about polluting your current code with more logic:

int menu() { //summarizing the above function in the OP
    int tercih; //declare our input variable
    //...
    scanf("%d", tercih); //read the input
    //...
    return tercih; //let the calling function know what was entered
}

void prompt() {
    int tercih;
    do {
        tercih = menu(); //call menu, and note the input value 'tercih'
    } while (tercih != 5); //continue looping until we meet the 'exit' condition
}

int main() {
    prompt();
    return 0;
}

You can even use this same approach to pull the logic for the individual menu options into their own function for handling the action.

CodePudding user response：

int main(){
    int x,y,tercih; // menu dizilimi sor, programın calismaya devam etmesi gerekiyor.
    do {
        printf("___ MENU ___\n");
        printf("1) Kare Kup\n");
        printf("2) Ucgen Tetrahedron\n");
        printf("3) Daire Kure\n");
        printf("4) Gauss Dagilimi\n");
        printf("5) Programdan cik\n");
        printf("Lutfen yapmak istediginiz islemi seciniz: ");
        scanf("%d",&tercih);
        switch(tercih) {
            case 1:
                printf("Lutfen kare ve kupun bir ayritinin uzunlugunu giriniz: ");
                scanf("%f",&x);
                printf("                 Alan   Hacim\nKare          %6.2f  %6.2f\nKup           %6.2f  %6.2f 
                ",x*x,0,6*(x*x),x*x*x); // sonuc 0.00 cikiyor?
            break;

            case 2:
                printf("Lutfen ucgen ve tetrahedronun bir ayritinin uzunlugunu giriniz: ");
                scanf("%d",&x);
                printf("                 Alan   Hacim\nUcgen         %6.2f  %6.2f\nTetra         %6.2f  %6.2f 
                ",sqrt(3)/4*x*x,0,sqrt(3)*x*x,sqrt(2)/12*x*x*x);
            break;

            case 3:
                printf("Lutfen daire ve kurenin yaricap uzunlugunu giriniz: ");
                scanf("%d",&x);
                printf("                 Alan   Hacim\nDaire          %6.2f  %6.2f\nKure            %6.2f  %6.2f ",M_PI*x*x,0,M_PI*x*x*x*4/3,4*M_PI*x*x);
            break;

            case 4:
                printf("Lutfen sirasiyla sapma ve boyut degerleri giriniz: "); //             soruyu anla yada sor 
                scanf("%d %d",&x,&y);
                printf("Sonuc: %d",x/y);
            break;

            case 5:
                printf("Programdan cikiliyor. ");
            break;

            default:
                printf("Yanlis islem girdiniz!");
            break;
        }
        } while(tercih != 5);
    return 0;
}

It's easy just use a "do while" loop like this. & instead of using "nested if" you can use "switch"