How to get own IP address in Python?-CodePudding

I want to receive unicast UDP packets sent to my machine's IPv4 address only, ignoring broadcast packets. This works if I hardcode the IP address like sock.bind(('192.168.1.69', 9)) but to make this code portable, I need a way to find the machine's own IP. I tried the below code, which isn't working:

host = socket.gethostname()
socket.gethostbyname(host)

The second line fails with: socket.gaierror: [Errno 8] nodename nor servname provided, or not known

If I instead do sock.bind(('0.0.0.0', 9)) then it works, but it also receives broadcast packets sent to 255.255.255.255 which I don't want. Using SOCK_DGRAM strips out the IP headers, so I don't think it's possible to inspect the destination IP address.

Edit: On macOS (and probably linux) I can get the destination IP using sock.recvmsg() after enabling socket.IP_RECVDSTADDR, but this doesn't work on Windows, which is what I need.

CodePudding user response：

To achieve this you need someone on the internet to tell you what is the public IP they see when you send them a package.

Check this thread provides some alternatives using services such as whatsmyip.org, api.ipify.org and ident.me.

Here is one example by @serge-stroobandt in the mentioned thread which is working for me:

import urllib.request
external_ip = urllib.request.urlopen('https://ident.me').read().decode('utf8')
print(external_ip)

Good luck!

CodePudding user response：

Use the fully qualified domain name search.

import socket
hostname = socket.getfqdn()
socket.gethostbyname_ex(hostname)

Gives you information like

('F12234.mydom.com', [], ['xxx.19.xxx.1', '10.195.3.101'])

The last list of IP's are the IP's currently associated to the networks your are connected to. If you have only one network connected, it should be one.