I have a command like below
md5sum test1.txt | cut -f 1 -d " " >> test.txt
I want output of the above result prefixed with File_CheckSum:
Expected output: File_CheckSum: <checksumvalue>
I tried as follows
echo 'File_Checksum:' >> test.txt | md5sum test.txt | cut -f 1 -d " " >> test.txt
but getting result as
File_Checksum:
adbch345wjlfjsafhals
I want the entire output in 1 line
File_Checksum: adbch345wjlfjsafhals
CodePudding user response:
echo
writes a newline after it finishes writing its arguments. Some versions of echo
allow a -n
option to suppress this, but it's better to use printf
instead.
You can use a command group to concatenate the the standard output of your two commands:
{ printf 'File_Checksum: '; md5sum test.txt | cut -f 1 -d " "; } >> test.txt
Note that there is a race condition here: you can theoretically write to test.txt
before md5sum
is done reading from it, causing you to checksum more data than you intended. (Your original command mentions test1.txt
and test.txt
as separate files, so it's not clear if you are really reading from and writing to the same file.)
CodePudding user response:
You can use command grouping to have a list of commands executed as a unit and redirect the output of the group at once:
{ printf 'File_Checksum: '; md5sum test1.txt | cut -f 1 -d " " } >> test.txt
CodePudding user response:
printf "%s: %s\n" "File_Checksum:" "$(md5sum < test1.txt | cut ...)" > test.txt
Note that if you are trying to compute the hash of test.txt
(the same file you are trying to write to), this changes things significantly.
Another option is:
{
printf "File_Checksum: "
md5sum ...
} > test.txt
Or:
exec > test.txt
printf "File_Checksum: "
md5sum ...
but be aware that all subsequent commands will also write their output to test.txt
. The typical way to restore stdout is:
exec 3>&1
exec > test.txt # Redirect all subsequent commands to `test.txt`
printf "File_Checksum: "
md5sum ...
exec >&3 # Restore original stdout
CodePudding user response:
Operator &&
e.g. mkdir example && cd example