Push item onto array on condition in one line-CodePudding

I want something like this and I would like to know if this is possible in JavaScript in one line, or I have to write an if statement

// these versions adds fasle to the array if condition = false
let arr = await getArray(params).push(condition && itemToAdd);
arr = await getArray(params).push((() => condition && itemToAdd)());

// this version adds undefined to the array if condition = false
arr = await getArray(params).push((() => { if (condition) return itemToAdd })());

(the reason I included the getArray part is cuz that's how it looks in my code and I don't actually save this array to a var arr only its being returned right away to its calling function, so that's why I don't want to add a line for the if statement...)

CodePudding user response：

Not sure why you want to do it in a single line, but this can work

let arr = [...await getArray(), itemToAdd].slice(0, condition ? undefined : -1);

Here we are pushing the itemToAdd in the array regardless of the condition, but we remove the last element (itemToAdd) if the condition is false.

CodePudding user response：

if you are working with reactjs then you can use useState for conditions

const [isCondition, setisCondition] = useState(false);

//but you need if/else to change useState

if(this_happens) {

setisCondition(true) } else { setisCondition(false) }

//you can do it as like

let arr = await getArray(params).push(isCondition && itemToAdd);