How to convert a string to array of strings made of characters in c ?-CodePudding

How to split a string into an array of strings for every character? Example:

INPUT:
string text = "String.";

OUTPUT:
["S" , "t" , "r" , "i" , "n" , "g" , "."]

I know that char variables exist, but in this case, I really need an array of strings because of the type of software I'm working on.

When I try to do this, the compiler returns the following error:

Severity    Code    Description Project File    Line    Suppression State
Error (active)  E0413   no suitable conversion function from "std::string" to "char" exists

This is because C treats stringName[index] as a char, and since the array is a string array, the two are incopatible. Here's my code:

string text = "Sample text";
string process[10000000];

for (int i = 0; i < sizeof(text); i  ) {
    text[i] = process[i];
}

Is there any way to do this properly?

CodePudding user response：

If you are going to make string, you should look at the string constructors. There's one that is suitable for you (#2 in the list I linked to)

for (int i = 0; i < text.size(); i  ) {
    process[i] = string(1, text[i]); // create a string with 1 copy of text[i]
}

You should also realise that sizeof does not get you the size of a string! Use the size() or length() method for that.

You also need to get text and process the right way around, but I guess that was just a typo.

CodePudding user response：

std::string is a container in the first place, thus anything that you can do to a container, you can do to an instance of std::string. I would get use of the std::transform here:

const std::string str { "String." };
std::vector<std::string> result(str.size());
std::transform(str.cbegin(), str.cend(), result.begin(), [](auto character) {
    return std::string(1, character);
});