Use python `regex` to get the string in parentheses-CodePudding

I want to get the string within parentheses from a string with complex parentheses.

Also, parentheses in strings within parentheses are correctly paired.

For example for the input abc[a[12] b[1] * (12 13)] = efg[14],

If the request comes in like this, abc[<Answer string>]

In this case <Answer string> is neither a[12, nor a[12] b[1, nor a[12] b[1] * (12 13)] = efg[14 , but a[12] b[1] * (12 13) .

This question was asked to modify the python code. I added an example I used.

input

self._vars[os.path.basename(b)[:-4]] = nn.Parameter(v, requires_grad=requires_grad)

output

setattr(self, os.path.basename(b)[:-4], nn.Parameter(v, requires_grad=requires_grad))

CodePudding user response：

You can try something like this:

import re
string = 'abc[a[12]   b[1] * (12   13)]'

match = re.findall('\[(. )\]', string)
print(match[0])

Output:

a[12]   b[1] * (12   13)

Here, \[(. )\] is matching everything between the outer square brackets.

CodePudding user response：

The idea is to extract everything within the square brackets of the pattern "blah[ ... ] = blah", so you can try the following regex.

The group including parenthesis (. ) matches any number of characters once or more times. The parenthesis control which parts of the string are returned after a match

import re
input = 'abc[a[12]   b[1] * (12   13)] = efg[14]'

output = re.findall('\[(. )\] \=', input)
for e in output:    #output is a list
    print(e)

Output:

a[12]   b[1] * (12   13)