function distribucion(x::Vector)
    for i in x
        if x[i] > 1
            return error("The values have to be between 0 and 1")
        elseif x[i] < 0
            return error("The values have to be between 0 and 1")
        end
    end 
end

x = collect(0:0.01:1) 
distribucion(x) Error:ArgumentError:invalid index:0.0 type Float64

Hi, I'm learning to use the Julia language but I've had some doubts and it's the following: how can I iterate a vector that contains decimals between 0 and 1? What happens is that I declared a function that receives a vector but when iterating and putting conditionals it shows me an error, could someone help me? Attached code of what I did along with the error that appears

I have this problem when i tried to run the code : Error:ArgumentError:invalid index:0.0 type Float64

CodePudding user response：

As already mentioned in the comment above:

function distribucion(x::Vector)
    for elem in x # iterate elements of vector
        if elem > 1 || elem < 0
            return error("The values have to be between 0 and 1, the value received was ", elem)
        end
    end
end

x =collect(0:0.01:1)
append!(x, 2.1) # test
distribucion(x)

CodePudding user response：

This code could be also written as:

function distribution(x)
    @assert all(0 .<= x .<= 1) "The values have to be between 0 and 1"
end

This works with any x (scalar, Vector, Matrix) - in Julia there is usually no need to limit the argument type. Note the dot operator (.) that vectorizes the comparison operation.

CodePudding user response：

It will be much faster if you provide a predicate to any or all functions in Julia because it avoids allocating a new array. The easiest in your case might be @assert all(i->0<=i<=1, x), but if you want a specific error message, you can use the following:

@assert all(i->0<=i<=1, x) "All values have to be between 0 and 1"

This has zero allocations and is about 4X faster than 0 .<= x .<= 1. It also works for scalars, vectors, or matrices.