I have this string:

"/--shirt-blue-/2346985"

I need to detect '/--' I solve using:

\/-{2}

But I need to detect if the string contains '/--' and the final contains '-/digit'

/--anything-/digit

How can I do that? Thanks.

CodePudding user response：

You can use

/\/--(.*?)-\/\d \z/

See the Rubular demo.

Details:

• \/-- - a /-- string
• (.*?) - Group 1: any zero or more chars other than line break chars as few as possible
• -\/ - a -/ string
• \d - one or more digits
• \z - end of string.

In Ruby,

puts "/--shirt-blue-/2346985"[/\/--(.*?)-\/\d \z/, 1]

shows shirt-blue.

CodePudding user response：

With your shown samples and attempts please try following regex:

^\/--(?:[^-]*-){2}\/\d $

Here is the Online demo for above used regex in Ruby.

Explanation: Adding detailed explanation for above shown regex.

^\/--          ##Matching starting /(escaped it) followed by 2 dashes.
(?:[^-]*-){2}  ##In a non-capturing group matching everything till 1st occurrence of - including - and this match 2 times.
               ##So basically this will match till 2 dashes.
\/\d $         ##Matching literal / followed by 1 or more digits at the end of the value.

CodePudding user response：

If there should be at least 1 char other than - in between:

^\/--(?:[^-] -) \/\d \z

Explanation

• ^ Start of string
• \/ Match /
• -- Match literally
• (?:[^-] -) Repeat 1 times matching any char except - and then match -
• \/\d Match / and 1 digits
• \z End of string

See a regex 101 demo and a Rubular demo