Regex pattern with accented characters-CodePudding

I am trying to get the words that start with a capital letter regardless of whether it has a special character or not in the word. Currently, my pattern only gets capital letters without accents.

I don't need numbers or hyphens, just accents or special characters in the letters.

pattern = r"\b[A-Z][a-z]*\b"
name = soup.select('h1.data-header__headline-wrapper')[0].text.strip()
name = re.findall(pattern, name)
name = " ".join(name)

CodePudding user response：

You need to pip install regex in your console and then use

import regex
pattern = r"\b\p{Lu}\p{Ll}*\b"
name = soup.select('h1.data-header__headline-wrapper')[0].text.strip()
name = regex.findall(pattern, name)
name = " ".join(name)

Here,

\b - a word boundary
\p{Lu} - an uppercase letter
\p{Ll}* - zero or more lowercase letters.

CodePudding user response：

If you want to use the core "re" module in Python, one option is to add to the list all Unicode letters you expect which are not in the range A-Z. Also, add the re.UNICODE flag to findall() function to allow for UNICODE characters.

For example:

s = "Ébc Ánna Apple Cámara Corazón Señor"
name = re.findall(r"(\b[A-ZÀÁÉ]\S*\b)", s, re.UNICODE)
print(name)

Output:

['Ébc', 'Ánna', 'Apple', 'Cámara', 'Corazón', 'Señor']