How did numpy add the @ operator?-CodePudding

How did they do it? Can I also add my own new operators to Python 3? I searched on google but I did not find any information on this.

CodePudding user response：

No, you can't add your own. The numpy team cooperated with the core Python team to add @ to the core language, It's in the core Python docs (for example, in the operator precedence table), although core Python doesn't use it for anything in the standard CPython distribution. The core distribution nevertheless recognizes the operator symbol, and generates an appropriate BINARY_MATRIX_MULTIPLY opcode for it:

>>> import dis
>>> def f(a, b):
...     return a @ b
>>> dis.dis(f)
  2           0 LOAD_FAST                0 (a)
              2 LOAD_FAST                1 (b)
              4 BINARY_MATRIX_MULTIPLY
              6 RETURN_VALUE

CodePudding user response：

Answering your second question,

Can I also add my own new operators to Python 3?

A similar question with some very interesting answers can be found here, Python: defining my own operators?

Recently in PyCon US 2022, Sebastiaan Zeeff delivered a talk showing how to implement a new operator. He warns that the implementation is purely educational though. However, it turns out you actually can implement a new operator yourself! Locally, of course :). You can find his talk here, and his code repository here. And if you think your operator could enhance Python Language, why not propose a PEP for it?