Is such a situation there are three tables are respectively the user user, trade orders, and money record user_money_record
Now according to the user to count their order total amount and account balance and total amount of top-up
User table
Id realname money
1 piece of xx 100
Wang xx 500
23 li xx 1500
The trade
Id uid realmoney
1 2 5000
2 1 1000
3 2 5000
4 3 10000
5 1 3500
User_money_record
Id uid money
1 2 5000
2 1 5000
3 2 2000
4 2 3000
5 3 5000
June 3, 5000
Table structure and data below
Statistics they order total amount and account balance and total amount of top-up
CodePudding user response:
Order total amount and the account balance and top-up respectively corresponding to the total amount which table which field
CodePudding user response:
reference 1st floor wangjian0228 response: order total amount and the account balance and top-up respectively corresponding to the total amount of which table which field It says clear oh user corresponding to the user table was the trade order user_money_record corresponding user prepaid phone records CodePudding user response:
The select Anderson d, A.r ealname, sum (B.r ealmoney), sum (c. oney) The from user A, trade B, user_money_record C Where Anderson, d=B.u id and Anderson, d=C.u id Group by Anderson, d CodePudding user response:
The reference 3 floor rucypli response: select Anderson d, A.r ealname, sum (B.r ealmoney), sum (c. oney) The from user A, trade B, user_money_record C Where Anderson, d=B.u id and Anderson, d=C.u id Group by Anderson d He had a balance, this can't do this CodePudding user response:
The reference 3 floor rucypli response: select Anderson d, A.r ealname, sum (B.r ealmoney), sum (c. oney) The from user A, trade B, user_money_record C Where Anderson, d=B.u id and Anderson, d=C.u id Group by Anderson d No, oh so there will be a repeat of calculation CodePudding user response:
select *,(select sum (realmoney) from the trade where uid=u.i d), (select sum (money) from user_money_record where uid=u.i d) From the user table u CodePudding user response:
refer to 6th floor ACMAIN_CHM response: select *, (select sum (realmoney) from the trade where uid=u.i d), (select sum (money) from user_money_record where uid=u.i d) From the user table u There is a select u.r ealname, u.m oney, (select sum (realmoney) from trade_history where uid=u.i d) as totalMoney, (select sum (money) from user_money_record where uid=u.i d) as allMoney The from user u CodePudding user response:
refer to 6th floor ACMAIN_CHM response: select *, (select sum (realmoney) from the trade where uid=u.i d), (select sum (money) from user_money_record where uid=u.i d) From the user table u In the wrong is the select u.n ame, t.r ealmoney, umr. Money from the user u Left the join (select the uid, sum (realmoney) as realmoney from trade group by uid) t on t.u id=u.i d Left the join (select uid, sum (money) as money from user_money_record group by uid) umr on umr) uid=uid CodePudding user response:
select *,(select sum (realmoney) from the trade where uid=u.i d), (select sum (money) from user_money_record where uid=u.i d) From the user table u CodePudding user response:
Agreed to advice on the 8th floor, CodePudding user response:
Built user table have a problem, you didn't also description fields and needs corresponding relation CodePudding user response:
The user list in the money represent? The balance? CodePudding user response:
Select sum (id) from ( Select count (nr. Goods_id) as id from ncp_release nr UNION ALL Select count (pr) goods_id) as id from pesticide_release pr UNION ALL Select count (fr. Goods_id) as id from fertilizer_release fr B) the as