I want to have the result without the whitespaces-CodePudding

let phrase = prompt('Enter the phrase')
function letter(phrase) {
  let frequency = {}
  for(letter of phrase){
    if(letter in frequency){
      frequency[letter]  
    }
    else{
      frequency[letter]=1
    }
  }
  return frequency
}
console.log(letter(phrase))

I want to have the result without the whitespaces. I have tried the split method but it then returns the count of the words not the letters.

CodePudding user response：

I want to have the result without the whitespaces.

If you want to check for a given condition (is the character a space) to perform a given action (ignore and continue) then what you're looking for is an if statement:

let phrase = prompt('Enter the phrase')
function letter(phrase) {
  let frequency = {}
  for(letter of phrase){
    // here
    if (letter === ' ') {
      continue;
    }

    if(letter in frequency){
      frequency[letter]  
    }
    else{
      frequency[letter]=1
    }
  }
  return frequency
}
console.log(letter(phrase))

There are a variety of ways to achieve the same end result. Alternate approaches could include:

Wrap the loop body in an opposite condition (if (letter !== ' ') to conditionally perform the entire loop body
Remove all whitespace from the string before processing the loop
Remove the whitespace property from the object after processing the loop

CodePudding user response：

here is an easy solution

 let phrase = prompt('Enter the phrase')
    function letter(phrase) {
     phrase = phrase.replaceAll(" ","");
     console.log(phrase)
      let frequency = {}
      for(letter of phrase){
        if(letter in frequency){
          frequency[letter]  
        }
        else{
          frequency[letter]=1
        }
      }
      return frequency
    }
    console.log(letter(phrase))

CodePudding user response：

I added one line to your code:

let phrase = prompt('Enter the phrase')
function letter(phrase) {
    let frequency = {}
    for(letter of phrase)
    {
        if(letter != ' ') // added a check here for whitespace   
        {  
            if(letter in frequency)
            {
               frequency[letter]  
            }
            else{
               frequency[letter]=1
            }
        }
    enter code here}
  return frequency
}
console.log(letter(phrase))

CodePudding user response：

Hope this will work for you.

let phrase = prompt('Enter the phrase').replace(/\s/g, "");
function letter(phrase) {
  let frequency = {}
  for(letter of phrase){
       if(letter in frequency){
          frequency[letter]  
       }
       else{
          frequency[letter]=1
       }
  }
  return frequency
}
console.log(letter(phrase))