Your big help-CodePudding

For help,,,,,

CodePudding user response:

(3) : tan x - sin x=sinx (1/cos x - 1)=(sin/cos x x) 1 - cos (x)=1/2 (sin/cos x x) * * * sinx sinx molecular denominator reduction of a fraction can get the answer

(4) : Taylor formula can expansion (Taylor formula content?)

CodePudding user response:

reference 1st floor zhouzheng11111 response:

(3) : tan x - sin x=sinx (1/cos x - 1)=(sin/cos x x) 1 - cos (x)=1/2 (sin/cos x x) * * * sinx sinx molecular denominator reduction of a fraction can get the answer

(4) : Taylor formula can expansion (Taylor formula content?)

Did not learn you say this formula

CodePudding user response:

refer to the second floor apure with honesty reply:

Quote: refer to 1st floor zhouzheng11111 response:
(3) : tan x - sin x=sinx (1/cos x - 1)=(sin/cos x x) 1 - cos (x)=1/2 (sin/cos x x) * * * sinx sinx molecular denominator reduction of a fraction can get the answer

(4) : Taylor formula can expansion (Taylor formula content?)

Not what you said this formula

Then use the limit formula: equivalent infinitesimal replacement

Tanx - sinx ~ (x ^ 3)/2
(1) + x ^ a - 1 ~ ax

Then available: the original type=- 3/2

CodePudding user response:

I'm sorry wrong
Then available: the original type=3

CodePudding user response:

Really thank you very much,,,,