User types too many inputs, exception python-CodePudding

just starting my journey with python. I would like to create a simple program that will take the input from the user and then do smth with it. But I am wondering what would happen if they put too many words. The error comes up and I cant get around with it.

name, surname = input("Full name: ").split()

try:
    print("Hello", name)
    print("Your login is:", surname   "ing")
except ValueError:
    print("Please type your Full name only!") #user type 3 words instead of 2

CodePudding user response：

You have to put the assignment inside the try, since that's where the execption is raised.

try:
    name, surname = input("Full name: ").split()
    print("Hello", name)
    print("Your login is:", surname   "ing")
except ValueError:
    print("Please type your Full name only!") #user type 3 words instead of 2

CodePudding user response：

I would suggest that you not use an exception in this way. I would check your input explicitly. Here's a way to do that:

while True:
    user_input = input("Full name: ").split()
    if len(user_input) == 2:
        break
    print("Please type your Full name only!") #user type 3 words instead of 2

name, surname = user_input
print("Hello", name)
print("Your login is:", surname   "ing")

Result:

Full name: Joe
Please type your Full name only!
Full name: Joe Blow a b c
Please type your Full name only!
Full name: Joe Blow
Hello Joe
Your login is: Blowing

Process finished with exit code 0

CodePudding user response：

You could ask for each value on its own like:

name = input("blabla")
surname = input("blabla")

or you could add it inside of the try/except which should also handle this error.

try:
    name, surname = input("Full name: ").split()
    print("Hello", name)
    print("Your login is:", surname   "ing")
except ValueError:
    print("Please type your Full name only!") #user type 3 words instead of 2