Pb C0031 error-CodePudding

Double I
I=double (sle_1. Text)
If iSt_3. Text=string (I)
Elseif 1000 & lt;=iSt_3. Text=string (I * 9/10)
Elseif 2000 & lt;=iSt_3. Text=string (I * 8/10)
The else 3000 & lt;=I
St_3. Text=string (I * 7/10)
End the if

Called the three C0031 error in the second and third then that line and else the line

CodePudding user response:

2000 & lt;=i<3000 of these very basic grammar or press F1 see help

CodePudding user response:

Ha ha, don't support the syntax

CodePudding user response:

Syntax written not so?

CodePudding user response:

reference IT_cainiao_ag reply: 3/f

for PB talents, to recommend

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