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to check the multiple of five and two

Time:10-16

#include

using namespace std;

int
main ()
{
  int multiple;
  cout << "Please give a number you want to check the multiple of: ";
  cin >> multiple;
  if ((multiple % 5 == 0), (multiple % 2 == 0));
 
    {           
      cout << multiple << " is multiple of five. " << endl;
      cout << multiple << " is the multiple of two. ";
    }
    
  else {
    
      cout << multiple << " is not multiple of five. " << endl;
      cout << multiple << " is not the multiple of two. ";
    }
    

  return 0;
}

I can't find the error in the code. It shows error in the else statement. I can't find the error in the code. It shows error in the else statement. I can't find the error in the code. It shows error in the else statement. I can't find the error in the code. It shows error in the else statement. I can't find the error in the code. It shows error in the else statement. I can't find the error in the code. It shows error in the else statement. I can't find the error in the code. It shows error in the else statement. I can't find the error in the code. It shows error in the else statement.

CodePudding user response:

You have syntax errors in line

if ((multiple % 5 == 0), (multiple % 2 == 0));
                       ^                     ^

It should be

if ((multiple % 5 == 0) || (multiple % 2 == 0))

CodePudding user response:

It shows an error in the else statement because C doesn't regard your if statement. C ignores your 'if' because you ended it with a semi-colon (;). When C sees a ' ; ' your if-statement has no effect - it just skips it. Also, your if-syntax is wrong. It shouldn't have a comma ( , ).

This is what you intended to do:

if (multiple % 5 == 0 && multiple % 2 == 0) {
  cout << multiple << " is a multiple of five. " << endl;
  cout << multiple << " is a multiple of two. ";
}
else {
  cout << multiple << " is not a multiple of five. " << endl;
  cout << multiple << " is not a multiple of two. ";
}
  •  Tags:  
  • c
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