how can i open a random text file in python?-CodePudding

i am trying to make a python program that randomly selects a text file to open and outputs the contents of the randomly selected text file

when i try running the code, i get this error

Traceback (most recent call last): File "//fileserva/home$/K59046/Documents/project/project.py", line 8, in o = open(text, "r") TypeError: expected str, bytes or os.PathLike object, not tuple

this is the code that i have written

import os
import random
os.chdir('N:\Documents\project\doodoo')
a = os.getcwd()
print("current dir is",a)
file = random.randint(1, 4)
text = (file,".txt")
o = open(text, "r")
print (o.read())

can somebody tell me what i am doing wrong?

CodePudding user response：

As your error message says, your text variable is a tuple, not a string. You can use f-strings or string concatenation to solve this:

# string concatenation
text = str(file)   ".txt"

# f-strings
text = f"{file}.txt"

CodePudding user response：

Your variable text is not what you expect. You currently create a tuple that could look like this: (2, ".txt"). If you want a string like "2.txt", you need to concatenate the two parts:

text = str(file)   ".txt"