How to count how many times I got the certain result-CodePudding

I am trying to write a code that would select 5 numbers between 1-10 and choose the maximum of them. I repeat the experiment 1000 times but I want to see how many times ı get the which result

    import random
for i in range (1,1000):
    b = random.choices(range(1, 11), k=5)
    max(b)
    print("The X value for %(n)s is {%(c)s} " % {'n': b, 'c': max(b)})

I want to see something like 10 occurring 500 times, 9 occurring 300 times. I tried to define a dictionary but couldn't manage to do so. Any help would be appreciated

CodePudding user response：

use the .count() method. Quite simple TBF. Here's how it works, in google's words.

The method is applied to a given list and takes a single argument. The argument passed into the method is counted and the number of occurrences of that item in the list is returned.

CodePudding user response：

You can create a dictionary with all the necessary keys, and then add 1 to the value each time that key comes up.

import random
number_counts = {x:0 for x in range(1,11)} # this will create a dictionary with 1-10 as keys and 0 as values
for i in range(1,1000):
    b = random.choices(range(1,11),k=5)
    m = max(b)
    number_counts[m]  = 1

print(number_counts)